Let each of the equal sides of the rhombus be a cm. Then,
Perimeter = a + a + a + a = 4a m According to the question,

                4a = 200







∴ Area of the rhombus

For ΔABC
a = 36.5 cm b = 55 cm c = 36.5 cm



Area of the ΔABC

∴ Area of the rhombus ABCD
= 2 Area of the ΔABC = 2 x 660 = 1320 cm²




∴ Length of the other diagonal is 48 cm. 

For ΔABC,   a = 34 cm b = 42 cm c = 20 cm





∴ Area of ΔABC

∴ Area of parallelogram ABCD
= 2 Area of triangle ABC
= 2 x 336 cm² = 672 cm²

For triangle
a = 15 cm b = 14 cm c = 13 cm

Let the height of the parallelogram be h cm. Then, area of the parallelogram
= Base x Height = 15 x h = 15h cm² According to the question,
Area of the parallelogram

                   = Area of the triangle

Hence, the height of the parallelogram is 5.6 cm.

For ΔACD
a = 28 m b = 41 m c = 15 m

Area of the quadrilateral ABCD
= Area of ΔABC + Area of ΔACD
= 180 m² + 126 m² = 306 m².